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Lateral Thinking Puzzles Found my book :D

#91 {lang:macro__useroffline}   cjjones {lang:icon}

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Posted 14 December 2003 - 08:04 AM

Beavis got that one biglaugh.gif

Score:
rabk:1
Alpha Weapon:4
Killerconvic:3
Phieta:1
headhunter:1
Trifang:1
vietpryde:1
beavis545:1

Fourteenth Riddle Thing: Six drinking glasses stand in a row, with the first three full of water and the next three empty. By handling and moving only one glass at a time, how can you arrange the six glasses so that no full glass stands next to another full glass, and no empty glass stands next to another empty glass. What is the minimum number of moves to solve this puzzle.

hehehehe, this one's good.

This post has been edited by cjjones: 14 December 2003 - 08:09 AM

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#92 {lang:macro__useroffline}   Killerconvic {lang:icon}

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Posted 14 December 2003 - 04:20 PM

push them all off the table biglaugh.gif
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#93 {lang:macro__useroffline}   polarbird111 {lang:icon}

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Posted 14 December 2003 - 06:11 PM

you take the second glass and pour it into the 5th glass? conf.gif
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#94 {lang:macro__useroffline}   Trifang {lang:icon}

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Posted 14 December 2003 - 07:19 PM

Toss them at polarbird and sees how, "polarish" she is...
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#95 {lang:macro__useroffline}   BubbaMurphy {lang:icon}

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Post icon  Posted 14 December 2003 - 07:34 PM

You could drink all the glasses that arn't empty. coolgleamA.gif
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#96 {lang:macro__useroffline}   Neraphym {lang:icon}

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Posted 14 December 2003 - 08:16 PM

Alright guys, you've gone a bit too far. Cjjones doesn't want us spamming in this topic. Please post only if you have something integligent to say. I like polarbird's answer, sounds right.
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#97 {lang:macro__useroffline}   cjjones {lang:icon}

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Posted 15 December 2003 - 06:01 AM

polarbird got it right, and now I've pulled myself out of the pit that is poverty, so I'll be giving a prize to the person with the highest score after the 30th Riddle Thing.

Score:
rabk:1
Alpha Weapon:4
Killerconvic:3
Phieta:1
headhunter:1
Trifang:1
vietpryde:1
beavis545:1
polarnird111:1

Fifteenth Riddle Thing: If you put a small coin into a an empty wine bottle and replace the cork, how would you get the coin out of the bottle without taking out the cork or breaking the bottle?
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#98 {lang:macro__useroffline}   Neraphym {lang:icon}

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Posted 15 December 2003 - 01:11 PM

Push the cork into the bottle, then turn it upside down. bluetongue.gif


Edit:
QUOTE
polarnird111:1

You might wanna fix that.

This post has been edited by Alpha Weapon: 15 December 2003 - 01:12 PM

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#99 {lang:macro__useroffline}   BubbaMurphy {lang:icon}

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Posted 15 December 2003 - 02:23 PM

You would just turn it upsidedown because if the coin was really small it would be smaller than the cork. grnwink.gif
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#100 {lang:macro__useroffline}   polarbird111 {lang:icon}

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Posted 15 December 2003 - 10:26 PM

You cut a coin sized slot in the cork? conf.gif

QUOTE
QUOTE 
polarnird111:1



You might wanna fix that.

ya you might but im sure it wasnt intentional
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#101 {lang:macro__useroffline}   Unrealblight {lang:icon}

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Posted 15 December 2003 - 11:27 PM

take out the cork and dont replace it ...mabey you never know

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#102 {lang:macro__useroffline}   Killerconvic {lang:icon}

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Posted 15 December 2003 - 11:48 PM

you fill it with water, then pull the coin out.

alpha is right, stop spamming.
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#103 {lang:macro__useroffline}   vietpryde {lang:icon}

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Posted 15 December 2003 - 11:53 PM

QUOTE (Killerconvic @ Dec 15 2003, 07:48 PM)
you fill it with water, then pull the coin out.

alpha is right, stop spamming.

they're not spamming. they are guessing to the riddle. except for bubbamurphy's second post.

my guess would probably be alpha's. it seems most likely.
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#104 {lang:macro__useroffline}   cjjones {lang:icon}

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Posted 16 December 2003 - 02:32 AM

Alpha was right...

Score:
rabk:1
Alpha Weapon:5
Killerconvic:3
Phieta:1
headhunter:1
Trifang:1
vietpryde:1
beavis545:1
polarird111:1

Sixteenth Riddle Thing: You are the treasurer in charge of the Royal mint, which produces a single type coin, the grote. There are ten machines producing grotes, one machine is producing grotes weighing one gram less than they should, each coin should weigh 10 grams. You have a set of broken scales which can be fixed to provide one single weigh of a single amount (no weight changes are allowed). Using the scales once you must identify the single faulty machine.

How do you do it?

This post has been edited by cjjones: 16 December 2003 - 02:40 AM

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#105 {lang:macro__useroffline}   Neraphym {lang:icon}

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Posted 16 December 2003 - 03:00 AM

I know a problem very similar to this, I PM you the answer so as not to spoil it from others.
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