[Neraphym]

Alrighty, see if you can follow my logic here.

lets say
a + b = c

If so then
(4-3)a + (4-3)b = (4-3)c
or
4a - 3a + 4b - 3b = 4c - 3c

This can be rearranged like so
4a + 4b - 4c = 3a + 3b - 3c

You can then factor out the coefficients from both sides giving you
4(a + b - c) = 3(a + b - c)

If you divide both sides by (a + b - c) then you are left with this
4=3


Obviously, 4 cannot equal 3, therefor this proof is wrong. Where is the flaw? First one to get it wins a prize.

Chocobo/Mog

[Crescens]

There have to be circumstances under which a + b = c ...

[©allum]

Algebra? Meh....

Errr... because 4 is greater than 3 therefore, it means that Leftyy hates algebra, and prefers english.

[Res]

*head explodes from thinking about it*

give me a while, and i might have an answer.

[Neraphym]

To cres: it is a given, just accept it.

Leftyy: I hate english

Powa: Good luck

I got another one too, but it involves a square root sign and I can't make one...

[Pirate]

since a+b=c then a+b-c would be 0 and thus 4(a+b-c) would be 0 and 3(a+b-c) would also be 0. and u cant divide by 0 otherwise u get an error

[obiwan22]

Psst: to make a square route sign pull up Word and go to insert: symbols; and choose the subset.

I won't even try to figure out what the answer is to this.

[Neraphym]

beavis got it, you can't divide by zero.

[Crescens]

* slaps self *

[Res]

ooh sweet! i gotta remember this for future reference!!!! haha


P.S. whats his prize? lol

[Neraphym]

Well I have a few rubies lying around, might as well give him one.

[©allum]

[Neraphym]

Any number divided by zero is considered to be undefined. If you do it on a calculator, you get a syntax error.

1 = -1
1 = sqrt(1) = sqrt(-1 * -1) = sqrt(-1) * sqrt(-1) = i * i = i^2 = -1

[©allum]

*blank stare*

Meh, a few days ago we did numbers that are divided by zero are undefined. Although, I did this like 3 years ago. I thought I was in the top year 9 class......

[Pirate]